c++ function to return mnm of 2 numbers

Condition : numbers should asked when function is executed:   #include <iostream> using namespace std; int minnummber() { // local variable declaration int result, num1, num2; cout << “Enter first number :: “; cin >> num1; cout << “Enter second number :: “; cin >> num2; if (num1 > num2) result = num2; else result = num1; return result; } int main () { cout << “Min is “<<minnummber(); return 0; }

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C++ Program to Average of 7 Numbers, Average of Odd Numbers and Average of Even numbers

#include <iostream> #include <string> using namespace std; int main() { int numb; float oddcount =0; float evencount = 0; float oddsum = 0; float evensum = 0; float allsum = 0; for (int k =1; k <= 7 ; k++) { cout << “Enter Number ::”<<k << endl; cin >> numb ; allsum = allsum + numb; while( numb % 2 == 0) { evencount = evencount+1; evensum = evensum + numb; break; } while( numb % 2 != 0) { oddcount = oddcount+1; oddsum = oddsum + numb; break; } } cout << “Average of All ::”<<allsum / 7 << endl; if (evencount != 0 ) cout << “Average of Even Numbers ::”<<evensum / evencount << endl; else cout << “No Even Numbers entered”<< endl; if (oddcount != 0) cout << “Average of Odd Numbers ::”<<oddsum / oddcount << endl; else cout << “No Odd Numbers entered”<< endl; }

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